The product of the first substitution (a primary amine) still possesses a lone pair on the nitrogen, making it a nucleophile itself.
This leads to successive substitutions: a primary amine reacts to form a secondary amine, which can then react to form a tertiary amine.
The final stage of substitution occurs when a tertiary amine reacts with the halogenoalkane to form a quaternary ammonium salt, where the nitrogen is bonded to four alkyl groups and carries a permanent positive charge.
| Condition | Major Product | Reason |
|---|---|---|
| Excess Ammonia | Primary Amine | High concentration of ensures it is the most likely nucleophile to collide with the halogenoalkane. |
| Excess Halogenoalkane | Quaternary Ammonium Salt | Ensures that every amine formed eventually reacts further until no more substitutions are possible. |
The nucleophilicity of amines generally increases from ammonia to secondary amines due to the positive inductive effect of alkyl groups, which increases electron density on the nitrogen.
Stoichiometry Check: Always remember that the overall balanced equation requires two moles of the nucleophile for every one mole of halogenoalkane to account for the salt formation (e.g., ).
Mechanism Precision: Ensure curly arrows start exactly at the lone pair or the center of a bond, and point clearly to the target atom or the atom receiving the electrons.
Intermediate Charges: Never forget to show the positive charge on the nitrogen atom in the intermediate step before the proton is removed.
A common error is assuming the reaction stops at the primary amine; without specific conditions, a mixture of products is almost always obtained.
Students often forget the role of the second nucleophile molecule, incorrectly showing the halogen ion () removing the proton instead of the excess ammonia/amine.
Confusing the classification: In amines, primary/secondary/tertiary refers to the number of alkyl groups on the nitrogen, not the carbon it is attached to.