Step 1: Nucleophilic Attack: The nucleophile uses its lone pair of electrons to form a new covalent bond with the carbonyl carbon, causing the bond of the to break.
This step converts the carbon from (planar) to (tetrahedral) hybridization, forming a negatively charged alkoxide intermediate.
Step 2: Protonation: The negatively charged oxygen atom in the intermediate attracts a proton () from the solvent or an added acid to form the final addition product.
A classic example is the addition of Hydrogen Cyanide (HCN), which requires a catalytic amount of alkali or cyanide salt (KCN) to generate sufficient ions for the initial attack.
Aldehydes are generally more reactive than ketones toward nucleophilic addition due to both electronic and steric factors.
Electronic Factor: Alkyl groups are electron-donating (+I effect). Ketones have two alkyl groups that reduce the partial positive charge on the carbonyl carbon more than the single alkyl group in aldehydes.
Steric Factor: The presence of two relatively large alkyl groups in ketones hinders the approach of the nucleophile compared to the smaller hydrogen atom in aldehydes.
Consequently, formaldehyde () is the most reactive carbonyl compound, followed by other aldehydes, with ketones being the least reactive.
Reduction: Aldehydes and ketones can be reduced to alcohols using reagents like Sodium Borohydride () or Lithium Aluminium Hydride ().
Aldehydes yield primary alcohols, while ketones yield secondary alcohols through the addition of hydride ions () to the carbonyl carbon.
Oxidation: Aldehydes are easily oxidized to carboxylic acids because of the presence of a hydrogen atom attached to the carbonyl carbon.
Ketones lack this hydrogen and do not undergo oxidation under mild conditions, allowing for chemical tests to distinguish between the two.
Tollens' Reagent: Also known as the 'silver mirror test', it uses ammoniacal silver nitrate. Aldehydes reduce to metallic silver, forming a mirror on the test tube wall.
Fehling's Solution: Contains ions in an alkaline medium. Aliphatic aldehydes reduce the blue to a brick-red precipitate of Copper(I) oxide ().
2,4-Dinitrophenylhydrazine (2,4-DNPH): This reagent reacts with both aldehydes and ketones to form yellow or orange crystalline precipitates, serving as a general test for the carbonyl group.
Iodoform Test: Specifically identifies methyl ketones (and ethanol/secondary alcohols with a methyl group) by forming a yellow precipitate of triiodomethane () when reacted with iodine and sodium hydroxide.
Chain Extension: Always remember that the reaction with is a key method for increasing the carbon chain length by one atom.
Chirality: Note that the addition of to an aldehyde (except formaldehyde) or an unsymmetrical ketone often creates a chiral center, resulting in a racemic mixture.
Reagent Specificity: Be careful with Fehling's solution; it typically gives a positive result with aliphatic aldehydes but may not react with aromatic aldehydes like benzaldehyde.
Visual Cues: In exam questions, look for keywords like 'silver mirror' (Tollens'), 'red precipitate' (Fehling's), or 'orange crystals' (2,4-DNPH) to identify the functional group present.