The area under the line of a velocity-time graph represents the displacement (or total distance travelled in a specific direction). This is because displacement is the product of velocity and time ().
For motion with constant acceleration, the area usually forms simple geometric shapes. You can calculate the total displacement by summing the areas of these shapes:
Rectangles: Used for periods of constant velocity ().
Triangles: Used for periods of uniform acceleration starting or ending at rest ().
If the graph is a curve, the acceleration is non-uniform. In such cases, displacement must be estimated by counting the squares underneath the curve on the grid and multiplying by the value of a single square.
| Feature | Distance-Time Graph | Velocity-Time Graph |
|---|---|---|
| Gradient | Represents Speed | Represents Acceleration |
| Flat Horizontal Line | Object is Stationary | Object has Constant Velocity |
| Area Under Curve | No physical significance | Represents Displacement |
| Curve | Changing Speed (Acceleration) | Changing Acceleration |
Check the Axes and Units: Always verify the units on both axes before calculating. If time is in minutes or distance in kilometres, convert them to standard SI units ( and ) to ensure the acceleration is in .
Use Large Gradient Triangles: When calculating the slope, draw a large triangle on the graph. This reduces the percentage error in your readings and is often a requirement for gaining full marks in practical-based questions.
Sanity Check the Area: When calculating displacement, ensure you have accounted for the entire area down to the x-axis (). Students often mistakenly stop at the lowest point of the line rather than the axis itself.
Describe Motion Precisely: Use terms like 'uniform acceleration', 'constant velocity', and 'deceleration' rather than just 'speeding up' or 'moving' to demonstrate technical proficiency.