Oxidation Numbers are theoretical charges assigned to atoms to track electron movement. They represent the charge an atom would have if all bonds to atoms of different elements were 100% ionic.
For pure elements in their natural state (e.g., , , ), the oxidation number is always zero. This reflects the lack of electron displacement between identical atoms.
In monatomic ions, the oxidation number is equal to the charge of the ion (e.g., has an oxidation state of , while is ).
The sum of oxidation numbers in a neutral compound must equal zero, while in a polyatomic ion, the sum must equal the overall charge of the ion.
The Half-Reaction Method involves splitting the overall equation into two separate parts: one for oxidation and one for reduction. This allows for precise balancing of both mass and charge.
Step 1: Balance elements other than Oxygen and Hydrogen first. Then, balance Oxygen by adding molecules and Hydrogen by adding ions (in acidic solutions).
Step 2: Balance charge by adding electrons () to the more positive side of each half-reaction. The number of electrons lost in oxidation must equal the number of electrons gained in reduction.
Step 3: Combine and Simplify by multiplying the half-reactions by integers so that the electrons cancel out when the equations are added together. Finally, verify that both atoms and charges are balanced on both sides.
| Feature | Oxidation | Reduction |
|---|---|---|
| Electron Movement | Loss of electrons | Gain of electrons |
| Oxidation Number | Increases (more positive) | Decreases (more negative) |
| Role in Reaction | Reducing Agent | Oxidizing Agent |
| Half-reaction side | Electrons are products () | Electrons are reactants () |
Always check the charge balance: A common mistake is balancing the atoms but leaving the net charges unequal on the reactant and product sides. The total charge on the left must equal the total charge on the right.
Identify the 'Spectator' Ions: In many redox problems, ions like or do not change oxidation state. Removing them to write a net ionic equation simplifies the identification of the species actually undergoing redox.
Watch for Oxygen and Hydrogen: In acidic media, use and . If the problem specifies basic media, balance as if in acid first, then add to both sides to neutralize into water.
Verify Oxidation States: If you calculate an oxidation state that seems impossible (e.g., Carbon as ), re-evaluate your assignments for Oxygen (usually ) and Hydrogen (usually ).